非是非Thinking, Express
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测验题目
问题：
How to make a 2 input XOR gate with only 2 input MUX and Inverter?
参考答案：
MUX(A, B, S) = A*S + B*S' # when S=1, output A XOR(A, B) = A^B = A*B' + A'*B = MUX(A', A , B) # Note: A'=NOT(A)